11/13/2023 0 Comments Java substring after characterRun Javascript on the JVM with Rhino/Nashorn « With JavaScript’s function: var str = "abc?def,ghi?jkl,mno,pqr?stu,vwx?yz" Ĭonsole.log( parts ) // (5) Ĭonsole.log( str.split('?') ) // (5) Ĭonsole.log( parts ) // (3) Ĭonsole.log( str.split(/\?(. String split = decodeMainURL.split(Pattern.quote( "?" ), 2) String decodeMainURL = code(myMainUrl, "UTF-8") String myMainUrl = "" + subURL +"&name=chrome&version=56" String subURL = URLEncoder.encode( paramUrl, "UTF-8") character and take a substring based on its position. If you just want to cut your string two places after the decimal point, you could just find the. From the doc: Returns a substring after the last occurrence of delimiter. This code is to ignore all characters after the first '' but works fine just for the first line if we read it all sequentially. val string '/abc/def/ghfj.doc' val result url.substringAfterLast ('/') println (result) // It will show ghfj.doc. readText userInputTextArea.getText () readTextAllInALine readText.replaceAll ('\ ', ' ') so the output after this is: Some Text Some Text again A comment A comment line Another Text Another Text againComment. I have face the same problem in URL parameters, To resoleve it i need to split based on first ? So that the remaing String contains parameter values and they need to be split based on &. If you want to use float formatting, you could parse your string as a float, and then use '.2f. In Kotlin you can use substringAfterLast, specifying a delimiter. However, note that substr() might not be supported on earlier versions of some browsers (esp. Now I want to remove that appended string on pressing back button. AFAIK, both substring() and indexOf() are supported by both Mozilla and IE. String split = str.split(quotedText, 2) // In my application, I am appending a string to create path to generate a URL. ? - \\? we have to escape sequence of some characters, to avoid use Pattern.quote( "?" ) String quotedText = Pattern.quote( "?" ) String str = "abc?def,ghi?jkl,mno,pqr?stu,vwx?yz" The string "boo:and:foo", for example, yields the following results with these parameters: Regex Limit Result Using Java String.split(String regex, int limit) with Pattern.quote(String s) Like its manual says, it works like this: A null input String returns null. That's more convenient than the one provided by Java out of the box if you don't need regular expressions. Three additional methods have been added: matches, replaceAll, and replaceFirst. The easiest way is to use StringUtilssplit(, char). The subSequence method has been added, as required by the CharSequence interface that String now implements. From jse1.4 String - Two split methods are new. Returns the index of the first (last) occurrence of the specified character, searching forward (backward) from the specified index. There are 12 characters with special meanings: the backslash \, the caret ^, the dollar sign $, the period or dot. output path.substring(0, path.lastIndexOf('/', 1)) given how the doc says. String str '123dance456' String substr 'dance' String parts str.split(substr) String before parts0 String after parts1 It is noteworthy that the second answer not work if we have more than one occurrence of the substring. before: 'I need this words removed taken please'. Note that split's argument is assumed to be a regular expression, so remember to escape special characters if necessary. Is there a command in java to remove the rest of the string after or before a certain word Example: Remove substring before the word 'taken'. Use the appropriately named method String#split().
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